WebCorrect option is A) Given A=tan6 ∘tan42 ∘B=cot66 ∘cot78 ∘ Find out: BA= cot66 ∘cot78 ∘tan6 ∘tan42 ∘=tan6 ∘tan42 ∘tan66 ∘tan78 ∘ Now take a look into the following … Web10 Jan 2024 · Explanation: x = tan81 + tan9 −(tan63+ tan27) = cot9 +tan9 −(cot27 + tan27) = (cos9)2 + (sin9)2 sin9 ⋅ cos9 − (cos27)2 +(sin27)2 sin27⋅ cos27. = 1 sin9 ⋅ cos9 − 1 sin27 ⋅ cos27. = 2 sin18 − 2 sin54. = 2 ⋅ sin54 −sin18 sin54 ⋅ sin18. = 4cos36⋅ sin18 cos36 ⋅ sin18.
AIIII 11. If A=tan6∘tan42∘ and B=cot66∘cot78∘, then - (A) A=2B
Web24 May 2024 · About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators ... WebElitmus Numerical Ability Question Solution - If a = tan6 tan 42 and B = cot66 cot 78 then (a) A = 2B (b) 1 AB 3 = (c) A = B (d) 3A = 2B. phone betting sites
If A = tan6tan42 and B = cot66cot78 - Maths - Meritnation
WebIf A=tan6°.tan42° and B=cot66°.cot78° find A/B cot70° +4cos70°=? The question is not clear, can you clarify?..... WebA=tan6°tan42° and B=cot66°cot78° A/B=tan6°tan42°tan66°tan78° Using tan(60-x)tanxtan(60+x)=tan3x for x=18° we get tan42°tan18°tan78°=tan54°...(1) for x=6° we get tan54°tan6°tan66°=tan18°...(2) Eliminating tan54°between (1) and (2) we get tan6°tan42°tan66°tan78°=1 Hence A/B=1. A=B Regards WebA=tan6°tan42° and B=cot66°cot78° A/B=tan6°tan42°tan66°tan78° Using tan(60-x)tanxtan(60+x)=tan3x for x=18° we get tan42°tan18°tan78°=tan54°...(1) for x=6° we get … how do you keep cut tulips from drooping